1. 

   utjhu New Member

   Найти tg a , если sin a =3/5 cos a = 5/12

    

   utjhu, 19 фев 2010

   #1
2. 

   Sergeygrodno New Member

   sin a =3/5
    tg a=(3/5)/*(1-9/25)=3/5*(5/4)=3/4
    cos a = 5/12
    tg a = (5/12)/*(25/144)=0,41/0,17=2,5
    

    

   Sergeygrodno, 19 фев 2010

   #2