Дано: у=x²sinx x₀=π/2 Решение: y'=x(2*sin(x)+x*cos(x)) у'(x₀)=y'(π/2)=π/2(2*sin(π/2)+π/2*cos(π/2))=π/2(2*1+π/2*0)=π/2*2=π