(x-x1)/(x2-x1)=(y-y1)(y2-y1) (x-(-3))/(2-(-3))=(y-6)/(9-6) (x+3)/5=(y-6)/3 3(x+3)=5(y-6) 3x+9=5y-30 3x-5y+39=0 Ответ: 3x-5y+39=0