1+sinx(cos^2 x - sin^2 x) = sin x + cos^2 x - sin^2 x 1 + sin x cos^2 x-sin^3 x=sinx(1 - sinx) + cos^2 x 1 - sin^3 x - sin x (1-sinx)=cos^2 x - sin x*cos^2 x 1 - sin^3 x = cos^2 x(1-sinx)+sinx*(1-sin x) (1-sin x)(1+sinx+sin^2 x) =( cos^2 x+sin x)(1-sin x) 1+sinx+sin^2 x = cos^2 x + sin x 1=cos 2x 2x=0 x=0 Ответ x= 2pi *n ; n прин z
