12-∛16y=∛32y^2, 12-2∛2y=2∛4y^2, 2(∛2y)^2+2∛2y-12=0, (∛2y)^2+∛2y-6=0, ∛2y=a, a^2+a-6=0, a1=-3, a2=2, ∛2y=-3, 2y=(-3)^3, y=-13,5, ∛2y=2, 2y=2^3, y=4.