4^x*4^x-3^x*4^x-2*3^x*3^x<=0 (4/3)^x=y y>0 (y^2-y-2)/y<=0 (y+1)(y-2)/y<=0 0<y<=2 (4/3)^x<=2 x<=1/log(2)(4/3) логарифм по основанию 2